G
Isaac Newton's Gravitational Constant {© 15/05/17}

Isaac Newton's gravitational constant has remained an enigma for more than 300 years. But it has now (at last) been solved:
G = aₒ.c² / mᵤ = 6.67359232004334E-11 m³ / kg.s²
This webpage is its mathematical description.

It is now self-evident, given that Newton's gravitational constant is based upon the properties of Quanta, that his laws of orbital motion also apply to the atom and that gravity is indeed magnetism:
thereby destroying the need for Quantum Theory and the associated unification theory!

The Mathematical Explanation

Planck gave us the means to determine the solution to Newton's gravitational constant 'G' using his formula for his 'length, but is actually an EME amplitude.

Its Units

Planck’s formula for length (λ) is as follows;

λ = √[G.ħ/c³]
G = λ².c³/ħ {m³ / kg.s²}

Its Value

Planck’s length (λ) is 1.61616952231128E-35 m, which allows us to find the value of G;
λ = √[G.ħ/c³]
G = λ².c³/ħ
G = 1.61616952231127E-35² x 299792459³ ÷ 1.05457207144921E-34
= 6.67359232004333E-11

Its formula

Using Planck’s length formula, we can establish the formula for ‘G’;
G = λ².c³/ħ
G = c².λ²/(Rₙ.mₑ.√γ)
aₒ/mᵤ = λ²/(Rₙ.mₑ.√γ) = 7.42537281943846E-28
because: aₒ = λ.ϵₑ / Rₙ.√γ & mᵤ = mₑ.ϵₑ
c².aₒ/mᵤ = 7.42537281943846E-28 x 8.98755184732665E+16 = 6.67359232004333E-11
G = c².aₒ/mᵤ = 6.67359232004334E-11 {m³ / s².kg}
Alternatively;
Given Newton's constant of proportionality (K) for the proton-electron pair:
G = (2π)².φ / mₚ.K = 6.67359232004334E-11 {m³ / kg.s²}
Or;
G = ξᵥ² / 4.mᵤ.K = 6.67359232004334E-11 {m³ / kg.s²}

Conclusion

Given the above evidence, which was available in the 1930s;
why was it necessary to fabricate its units (N.m²/kg²) from Newton's force-law formula?
why is it still necessary to estimate its value?
why has nobody applied his laws to the atom?

Moreover, Newton's and Kepler's formulas for the constant of proportionality (K) gave us the correct units for Newton's gravitational constant (G) 300-years ago;
K = (2π)² / G.m = t²/a³
G = (2π)²/m . a³/t² {m³ / s².kg}

Today we have accurate values for Earth's; orbital 'a', orbital period (t), and the mass of its force-centre (the sun), so we also have an accurate value for 'G';
(2π)² ÷ 1.9885E+30 x ((1.47095E+11+1.52094196155084E+11)/2)³ ÷ 31558118.40² = 6.67359232004334E-11

And by a remarkable coincidence:
G = c².aₒ / mᵤ = 6.67359232004334E-11 {m³ / s².kg}
confirming that gravity is not based upon the mass of matter, it is based upon the particles of which it comprises.
And because atomic particles are the source of magnetism (due to non-polar magnetic charge) we can safely claim that Isaac Newton's gravitational constant, actually applies to magnetic attraction; gravity is magnetism.